4v+12=8(1[v+2]1)

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Solution for 4v+12=8(1[v+2]1) equation: 


Simplifying
4v + 12 = 8(1[v + 2] * 1)

Reorder the terms:
12 + 4v = 8(1[v + 2] * 1)

Reorder the terms:
12 + 4v = 8(1[2 + v] * 1)

Reorder the terms for easier multiplication:
12 + 4v = 8(1 * 1[2 + v])

Multiply 1 * 1
12 + 4v = 8(1[2 + v])
12 + 4v = 8([2 * 1 + v * 1])
12 + 4v = 8([2 + 1v])
12 + 4v = (2 * 8 + 1v * 8)
12 + 4v = (16 + 8v)

Solving
12 + 4v = 16 + 8v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-8v' to each side of the equation.
12 + 4v + -8v = 16 + 8v + -8v

Combine like terms: 4v + -8v = -4v
12 + -4v = 16 + 8v + -8v

Combine like terms: 8v + -8v = 0
12 + -4v = 16 + 0
12 + -4v = 16

Add '-12' to each side of the equation.
12 + -12 + -4v = 16 + -12

Combine like terms: 12 + -12 = 0
0 + -4v = 16 + -12
-4v = 16 + -12

Combine like terms: 16 + -12 = 4
-4v = 4

Divide each side by '-4'.
v = -1

Simplifying
v = -1

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